Eliminate duplicates from LL

You have been given a singly linked list of integers where the elements are sorted in ascending order. Write a function that removes the consecutive duplicate values such that the given list only contains unique elements and returns the head to the updated list.

 Input format :

The first line contains an Integer 't' which denotes the number of test cases or queries to be run. Then the test cases follow.

The first and the only line of each test case or query contains the elements(in ascending order) of the singly linked list separated by a single space.

 Remember/Consider :

While specifying the list elements for input, -1 indicates the end of the singly linked list and hence, would never be a list element.

 Output format :

For each test case/query, print the resulting singly linked list of integers in a row, separated by a single space.

Output for every test case will be printed in a seperate line.

Constraints :

1 <= t <= 10^2
0 <= M <= 10^5
Time Limit: 1sec

Where 'M' is the size of the singly linked list.

Sample Input 1 :

1
1 2 3 3 4 3 4 5 4 5 5 7 -1

Sample Output 1 :

1 2 3 4 3 4 5 4 5 7 

Sample Input 2 :

2
10 20 30 40 50 -1
10 10 10 10 -1

Sample Output 2 :

10 20 30 40 50
10

	class Node:
	def __init__(self,data):
	self.data=data
	self.next=None
	def LinkedList(arr):
	head=None
	tail=None
	if len(arr)<1:
	return
	else:
	for i in arr:
	if i ==-1:
	break
	NewNode=Node(i)
	if head is None:
	head=NewNode
	tail=NewNode
	else:
	tail.next=NewNode
	tail=NewNode
	return head
	def printLL(head):
	while head is not None:
	print(head.data,end=" ")
	head=head.next
	# This function removes duplicates from list
	def removeDuplicates(head):
	temp = head
	if temp is None:
	return
	while temp.next is not None:
	if temp.data == temp.next.data:
	new = temp.next.next
	temp.next = None
	temp.next = new
	else:
	temp = temp.next
	return head
	t=int(input())
	for i in range(t):
	arr=list(map(int,input().split()))
	printLL(removeDuplicates(LinkedList(arr)))

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